宝宝家用滑梯:(2x+5)^2-(2x-5)^2
来源:百度文库 编辑:高考问答 时间:2024/07/03 09:14:01
(2x+5)^2-(2x-5)^2
(2x+5)^2-(2x-5)^2
=[(2x+5)+(2x-5)]*[(2x+5)-(2x-5)]
=(4x)*(10)
=40x
原试=2*(2x+5-(2x-5))
=2*(2x+5-2x+5)
=2*10
=20
分解因式:x^5+x^2+x
-x*x^5-(x^2)^3-(-2x^3)^2
(x+5)(x+2)(x-1)(x-4)<1600
x^6+x^5+x^4+x^3+x^2+x+1=0
5x-2/(x+2)(x-2)-(x-1)(x+2)/(x+2)(x-2)=0
问几道题目:1.(2*x*x*x+x*x-11x-5)/(x+2)的余式是 .
计算[(x-1)/(x-2)-(x-2)(x-3)-(x-3)/(x-4)+(x-4)(x-5)]/(2x-7)
谁会解这道题:(X-5)/(X-7)+(X-2)/(X-4)=(X-3)/(X-5)+(X-4)/(X-6)求X的值
2x^5-5x^4-11x^3+23x^2+9x-18
(x-4)(x-2)-(x-1)(x+3),其中x=-2/5