7.25冰法一键输出宏:一道简单的高一数学题,谢谢
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解不等式x^(log[2]x-1)>16/x
显然x>0
x^(log[2]x-1)>16/x
x^(log[2]x)>16
由于当x>4时x^(log[2]x)>x^2>16,而当0<x≤4时x^(log[2]x)≤x^2≤16,所以解为x>4
显然x>0
x^(log[2]x-1)>16/x
x^(log[2]x)>16
由于当x>4时x^(log[2]x)>x^2>16,而当0<x≤4时x^(log[2]x)≤x^2≤16,所以解为x>4