新日恒力董事长:一道分式计算题
来源:百度文库 编辑:高考问答 时间:2024/07/08 10:05:09
1/a-1 - 2/1-a^2
要有步骤的
要有步骤的
1/(a-1)-2/(1-a^2)
=(a+1)/(a-1)(a+1)+2/(a^2-1)
=(a+1)/(a^2-1)+2/(a^2-1)
=(a+3)/(a^2-1)
1/(a-1)-2/(1-a^2)
=1/(a-1)+2/(a-1)*(a+1)
=(a+3)/(a^2-1)
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来源:百度文库 编辑:高考问答 时间:2024/07/08 10:05:09
1/(a-1)-2/(1-a^2)
=(a+1)/(a-1)(a+1)+2/(a^2-1)
=(a+1)/(a^2-1)+2/(a^2-1)
=(a+3)/(a^2-1)
1/(a-1)-2/(1-a^2)
=1/(a-1)+2/(a-1)*(a+1)
=(a+3)/(a^2-1)